-16x^2+24.25x+4=0

Solution for -16x^2+24.25x+4=0 equation:

-16x^2+24.25x+4=0

a = -16; b = 24.25; c = +4;
Δ = b2-4ac
Δ = 24.252-4·(-16)·4
Δ = 844.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24.25)-\sqrt{844.0625}}{2*-16}=\frac{-24.25-\sqrt{844.0625}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24.25)+\sqrt{844.0625}}{2*-16}=\frac{-24.25+\sqrt{844.0625}}{-32}
$